Question

# There is a uniform electric field of strength $$10^{3}V/m$$ along $$y-axis$$. A body of mass $$1 g$$ and charge $$10^{-6}C$$ is projected into the field from origin along the positive $$x-axis$$ with a velocity $$10 m/s$$. Its speed in m/s after $$10s$$ is (neglect gravitation) :

A
10
B
52
C
102
D
20

Solution

## The correct option is C $$10\sqrt{2}$$Velocity in $$x$$ direction remains constant i.e, $$v_{x}=10\ m/s$$Now acceleration is only in y direction$$a=\dfrac{qE}{m}$$$$a=\dfrac{10^{3}\times 10^{-6}}{1\times 10^{-3}}$$$$\therefore$$ Velocity in y direction $$v_{y}=a\times t$$$$v_{y}=10m/s$$$$\therefore v=10\hat{x}+10\hat{y}$$$$\left | v \right |=10\sqrt{2}$$PhysicsNCERTStandard XII

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