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Question

There is an air bubble of radius 1.0 mm in a liquid of surface tension 0.075 Nm-1 and density 1000 kg m-3. The bubble is at a depth of 10 cm below the free surface. By what amount is the pressure inside the bubble greater than the atmospheric pressure? Take g = 9.8 m s-2.


A

980 Pa

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B

2260 N/m2

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C

1130 N/m2

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D

1260 Pa

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Solution

The correct option is C

1130 N/m2



Let the atmospheric pressure be P0. The pressure of the liquid just outside the bubble is
P=P0+hρg
The pressure inside the bubble is
P=P+2sr=P0+hρg+2sr
or,PP0
=(10cm)(1000 kgms3)(9.8ms2)+2×0.075Nm11.0×103m
=980Nm2+150Nm2
=1130 pa

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