CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:
X2(g)2X(g)
The standard reaction Gibbs energy, ΔrG0, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar K1mol1)

The equilibrium constant Kp for this reaction at 298 K, in terms of βequilibrium, is:

A
8β2equilibrium2βequilibrium
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8β2equilibrium4β2equilibrium
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4β2equilibrium2βequilibrium
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4β2equilibrium4β2equilibrium
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 8β2equilibrium4β2equilibrium
X2(g)2X(g)1 01βe2 βe
Total number of moles at equilibrium
1βe2+βe
1+βe2
Kp=(px)2px2
=(βe×21+βe2)2(1βe2)×21+βe2=2β2e1β2e44Kp=8β2e4β2e

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Le Chateliers Principle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon