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Question

# Three ammeters A, B and C of resistances RA,RB and RC respectively are joined as shown. When some potential difference is applied across the terminals T1 and T2, their readings are IA,IB and IC respectively

A
IA=IB
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B
IARA+IBRB=ICRC
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C
IAIC=RCRA
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D
IBIC=RCRA+RB
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Solution

## The correct options are A IA=IB B IARA+IBRB=ICRC D IBIC=RCRA+RBAccording to the given data, ammeters A and B are connected in series hence will read the same current through them i.e. IA=IB ..........(1)Now, applying KVL we get,IARA+IBRB−ICRC=0IARA+IBRB=ICRC ............(2)Using equation (1) in (2) we getIBRA+IBRB=ICRCIB(RA+RB)=ICRCIBIC=RC(RA+RB)IAIC=RC(RA+RB) ........from(1)

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