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Byju's Answer

Standard XII

Mathematics

Fundamental Laws of Logarithms

Three blocks ...

Question

Three blocks A, B and C weighing 1, 8 and 27 kg respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface. $T_{3}$ is equal to 36 N. Then $T_{2}$ is

18 N

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9 N

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3.375 N

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1.25 N

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Solution

The correct option is B 9 N
$T_{2} = (m_{A} + m_{B}) \times \frac{T_{3}}{m_{A} + m_{B} + m_{C}}$
$T_{2} = (1 + 8) \times \frac{36}{(1 + 8 + 27)} = 9 N$

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Similar questions

Q. Three blocks

A

B

and

C

weighing

1, 8

and

27 kg

respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface. If

T_{3}

is equal to

36 N

, then

T_{2}

Q. Three blocks

A

B

and

C

weighing

1 k g, 8 k g

and

27 k g

respectively are connected as shown in the figure, with an inextensible string and are moving on a smooth surface. If tension

T_{3}

is equal to

36 N

, then tension

T_{2}

Q. Three blocks

A, B

and

C

weighing

1 k g, 8 k g

and

27 k g

respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface.

T_{3}

is equal to

36 N

. then

T_{2}

Three blocks A, B and C weighing 1, 8 and 27 kg respectively are connected as shown in the figure with an in extensible string and are moving on a smooth surface. $T_{3}$ is equal to 36 N. Then $T_{2}$ is

Q. Three blocks

A

B

and

C

weighing

1

8

and

27 kg

respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface.

T_{1}

is equal to

2 N

. Then

T_{3}

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Three blocks A, B and C weighing 1, 8 and 27 kg respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface. T3 is equal to 36 N. Then T2 is

The correct option is B 9 NT2=(mA+mB)×T3mA+mB+mC T2=(1+8)×36(1+8+27)=9 N

Three blocks A, B and C weighing 1, 8 and 27 kg respectively are connected as shown in the figure with an inextensible string and are moving on a smooth surface. $T_{3}$ is equal to 36 N. Then $T_{2}$ is

The correct option is B 9 N
$T_{2} = (m_{A} + m_{B}) \times \frac{T_{3}}{m_{A} + m_{B} + m_{C}}$
$T_{2} = (1 + 8) \times \frac{36}{(1 + 8 + 27)} = 9 N$