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Question

Three capacitors each of capacitance C and d breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be


A
C3,V3
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B
3C,V3
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C
C3,3v
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D
3C, 3V
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Solution

The correct option is C $$\frac { C } { 3 } , 3 \mathrm { v }$$
In series combination
Veff $$= V + V + V = 3V$$ and $$\dfrac{1}{C_{eq}} = \dfrac{1}{C}+ \dfrac{1}{C} + \dfrac{1}{C}$$
$$C_{eq} = \dfrac{C}{3}$$
Thus, the capacitance & breakdoum voltage are
$$\dfrac{C}{3}$$ & $$3v$$ 

1203459_1398780_ans_28ba7238d5924fdfba7dd7599e8d2929.jpg

Physics
NCERT
Standard XII

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