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Question

# Three capacitors of capacitance 3 μF, 10 μF and 15 μF are connected in series to a battery of 100 V. The charge on 15 μF is

A
50 μC
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B
100 μC
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C
200 μC
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D
280 μC
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Solution

## The correct option is C 200 μC In series combination, the equivalent capacitance is given by 1Ceq=1C1+1C2+1C3 ⇒1Ceq=13+110+115=12 ⇒Ceq=2 μF Moreover, in a series combination, the charge on each capacitor is the same, which is the same as the charge on the equivalent capacitor. Now using Q=CV, we get Q=2μF×100V=200μC Hence, option (c) is correct. Key Concept : Charge on a capacitor in a series arrangement in a circuit.

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