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Question

Three circles C1,C2 and C3 with radii r1,r2 and r1+r2 respectively are such that C1 and C2 touch each other externally and C3 internally. Another circle with radius r3 touches all the three circles. If r1>r2>r3 and r1,r2,r3 are in A.P. then (r1r2)3 is

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Solution


cos(CDA)=cos(CDB)AD2+DC2AC22AD.DC=(BD2+DC2BC22BD.DC)(r1+r2r1)2+(r1+r2r3)2(r1+r3)22r2(r1+r2r3)=(r1)2+(r1+r2r3)2(r2+r3)22r1(r1+r2r3)2r2=r1+r3 as they are in A.P(r2)2+(2r1r2)2(2r2)22r2(2r1r2)=(r1)2+(2r1r2)2(3r2r1)22r1(2r1r2)
By solving this we get
(r1r2)3=2

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