Let x be the radius of Circle A
Let y be the radius of Circle B
Let z be the radius of Circle C
AB=x+y=10–eq.1
BC=y+z=14–eq.2
CA=z+x=16–eq.3
From eq.3,
z=16−x
Substituting this in eq.2
y+16–x=14
⟹y–x=1−eq.4
Solving eq.1 and eq.4
x=6
z=16−6=10
y=10−6=4
Radii of circles are 6,10 and 4