CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three coins are tossed together. Find the probability of getting:

(i) exactly two heads

(ii) at least two heads

(iii) at least one head and one tail.

Open in App
Solution

Three coins are tossed
n(S)=23=S

(i) E be the event of getting exactly two heads
E = {HHT, HTH, THH}

n(E)=3

P(E)=38

(ii) E at least two heads (two or 3 heads)

E=HHH,HHT,THH,HTHn(E)=4

P(e)=48=12

P(E)=12

(iii) At least one head and one tail

E = {HTT, THT, TTH, HHT, HTH, THH}

n(E)=6

P(E)=68=34

P(E)=34


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Defining Probability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon