Three coins are tossed together. Find the probability of getting:
(i) exactly two heads
(ii) at least two heads
(iii) at least one head and one tail.
Three coins are tossed
∴n(S)=23=S
(i) E be the event of getting exactly two heads
∴ E = {HHT, HTH, THH}
∴ n(E)=3
∴P(E)=38
(ii) E at least two heads (two or 3 heads)
∴E=HHH,HHT,THH,HTHn(E)=4
∴P(e)=48=12
P(E)=12
(iii) At least one head and one tail
∴ E = {HTT, THT, TTH, HHT, HTH, THH}
∴ n(E)=6
∴P(E)=68=34
P(E)=34