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Question

Three coins are tossed together. Find the probability of getting: 

(i) exactly two heads 

(ii) at least two heads 

(iii) at least one head and one tail. 


Solution

Three coins are tossed 
n(S)=23=S

(i) E be the event of getting exactly two heads 
  E = {HHT, HTH, THH}

 n(E)=3 

P(E)=38

(ii) E at least two heads (two or 3 heads) 

E=HHH,HHT,THH,HTHn(E)=4 

P(e)=48=12

P(E)=12

(iii) At least one head and one tail

E = {HTT, THT, TTH, HHT, HTH, THH}

 n(E)=6

P(E)=68=34

P(E)=34


Mathematics
RD Sharma
Standard XI

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