Three congruent circles with centres $A$ , $B$ and $C$ and with radius $5 c m$ each, touch each other in points $D, E, F$ as shown in the figure.
The perimeter of $△ A B C$ in cm is

15cm

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60cm

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45cm

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30cm

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Solution

The correct option is D 30cm
Radius of each circles is equal
therefore $A D = D B = B E = E C = C F = F A$
Perimeter of a circle is sum of thier three sides
So, Perimeter of triangle $A B C = A B + B C + C A$
= $A D + D B = B E + E C + C F + F A$
= 6.AD
= $30 c m$

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Three congruent circles with centres A, B and C and with radius 5cm each, touch each other in points D,E,F as shown in the figure.The perimeter of △ABC in cm is

The correct option is D 30cmRadius of each circles is equaltherefore AD=DB=BE=EC=CF=FA Perimeter of a circle is sum of thier three sidesSo, Perimeter of triangleABC=AB+BC+CA=AD+DB=BE+EC+CF+FA = 6.AD= 30cm

Three congruent circles with centres $A$ , $B$ and $C$ and with radius $5 c m$ each, touch each other in points $D, E, F$ as shown in the figure.
The perimeter of $△ A B C$ in cm is

The correct option is D 30cm
Radius of each circles is equal
therefore $A D = D B = B E = E C = C F = F A$
Perimeter of a circle is sum of thier three sides
So, Perimeter of triangle $A B C = A B + B C + C A$
= $A D + D B = B E + E C + C F + F A$
= 6.AD
= $30 c m$