CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

three cubes of iron whose edges are 6 cm, 8 cm and 10 cm,respectively are melted and formed into a single cube. Find the edge of the new cube formed.


Solution

Edge of the first cube $$= 6 cm$$ 
volume of the first cube $$= (side)^3 = (6)^3 cm^3$$
Edge of the second cube $$= 8 cm$$
Volume of the second cube $$= (side)^3 = (8)^3 cm^3$$
 Edge of the third cube $$= (side)^3 = (10)^3 cm^3$$
 Let $$'a'$$ be side edge of the new formed cube.
 Volume of the cube $$=$$ Volume of the first cube $$+$$ volume of the second cube $$+$$ volume of the third cube 
 $$a^3 = 6^3 + 8^3 + 10^3$$
 $$=216 + 512 + 1000$$
 $$=1728$$
or $$a = 12$$ 
 Edge of the new cube is $$12 cm.$$
 

Mathematics
RS Agarwal
Standard X

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image