Question

Three digital clocks $A,B$ and $C$ run at different rates and do not have simultaneous reading of zero. Figure shows simultaneous reading on pairs of the clocks for four occasions. (At the carliest occasion, for example, $B$ reads $25.0$ and $C$ reads $92.0s$) If two events are $600s$ apart on clock $A$, how far apart are they on $B$?
When clock $A$ reads $400s$, what does clock $B$ read?

Answer 1

A $(512-312)=200s$ difference on clock $A$= $(290-125)=165s$ on clock $B$

$\therefore 600s$ on clock $A=\frac{165}{200}\times 600=495s$ on clock $B$

400-312=88s difference on clock A corresponds to= $\frac{165}{200}\times 88=72.6s$ on clock B

Therefore clock B reads= 125+72.6=197.6s