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Question

Three discs A,B and C having radii 2,4 and 6 cm, respectively, are coated with carbon black. Wavelengths for maximum intensity for the three discs are 300,400 and 500 nm, respectively. If QA,QB and QC are powers emitted by A,B and C, respectively, then

A
QA will be maximum
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B
QB will be maximum
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C
QC will be maximum
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D
QA=QB=QC
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Solution

The correct option is A QB will be maximum
According to Wein's displacement law λT=constant
so the ratio of temperatures of the three discs will be 13:14:15=20:15:12
and the ratio of the area of the discs=1:4:9
Now according to Stephan's law QαA×T4
so ratio Qa:Qb:Qc=1×(20)4:4×(15)4:9×(12)4
on solving we will get that Qb is maximum

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