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Question

Three faraday of electricity is passed through three electrolytic cells connected in series containing Ag+,Ca2+ and Al3+ ions respectively. The molar ratio in which the three metal ions are liberated at the electrodes is:


  1. 1 : 2 : 3

  2. 3 : 2 : 1

  3. 6 : 3 : 2

  4. 3 : 4 : 2


Solution

The correct option is C

6 : 3 : 2


Ag++eAgCa2++2eCaAl3++3eAl∣ ∣ ∣For 1 mole ofAg+,Ca2+,Al3+1mole of e,2 mole ofeand 3 mole of erequired respectively.

for 1 mole e=1 faraday 1  mole of Ag+

for 1 mole e=1 faraday 12 mole of Ca2+

for 1 mole e=1 faraday 13 mole of Al3+

So for  3 faraday 1×3,12×3,13×3

3:32:1 Or 6:3:2

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