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Question

Three forces are acting on the block as shown in figure.


Find work done by net force if block moves 10 m in horizontal direction. Given that [F1=20 N,F2=52 N,F3=10 N]

A
50 J
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B
100 J
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C
75 J
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D
No work done as friction is absent
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Solution

The correct option is A 50 J
Let net force in horizontal direction be Fnet
Fnet=F1cos60+F3cos90F2cos45
Fnet=20×12+052×12=105=5 N


Displacement in horizontal direction S=10 m
Work done by net force, W =Fnet×S
W=5×10
W=50 J

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