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Question

# Three large identical conducting parallel plates carrying charge +Q,âˆ’Q and +2Q respectively, are placed as shown in the figure. If EA,EB, and EC refer to the magnitudes of the electric fields at points A,B and C respectively, then

A
EA>EB>EC
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B
EA=0 and EC>EB
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C
EA=0 and EB>EC
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D
EA=0 and EB=EC
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Solution

## The correct option is B EA=0 and EC>EBE1, E2 and E3 are electric fields due to plates 1, 2 and 3 respectively. Let A is the surface area throught which the electric field lines pass perpendicularly. Net electric field at point point A: EA=E1+E2−E3 Substituting the values of electric field from figure, EA=Q2ϵ0A+Q2ϵ0A−2Q2ϵ0A ∴EA=0 Now net electric field at point B: EB=E1−E2−E3 Substituting the values of electric field from figure, EB=Q2ϵ0A−Q2ϵ0A−2Q2ϵ0A ∴EB=−Q2ϵ0A Similarly, net electric field at point C: EC=E1−E2+E3 Substituting the values of electric field from figure, EC=Q2ϵ0A−Q2ϵ0A+2Q2ϵ0A ∴EC=Qϵ0A Hence, EC>EB and option (b) is correct answer.

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