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Question

Three large parallel plates have uniform surface charge densities as shown in the figure. The electric field intensity at point P is :

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A
4σϵ0^k
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B
3σ2ε0^k
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C
5σ2ε0^k
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D
5σ2ε0^k
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Solution

The correct option is D $$-\frac{5\sigma }{2\varepsilon _0}\hat{k}$$
Resultant electric field at point P
$$==\left ( \frac{\sigma}{2 \epsilon_0} +\frac{\sigma}{2 \epsilon_0}+\frac{3\sigma}{2 \epsilon_0}\right )(-\hat{k})$$
$$=-\frac{5 \sigma}{2 \epsilon}\hat{k}$$
Ans:(D)
137427_75731_ans.png

Physics
NCERT
Standard XII

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