Question

# Three large parallel plates have uniform surface charge densities as shown in the figure. The electric field intensity at point P is :

A
4σϵ0^k
B
3σ2ε0^k
C
5σ2ε0^k
D
5σ2ε0^k

Solution

## The correct option is D $$-\frac{5\sigma }{2\varepsilon _0}\hat{k}$$Resultant electric field at point P$$==\left ( \frac{\sigma}{2 \epsilon_0} +\frac{\sigma}{2 \epsilon_0}+\frac{3\sigma}{2 \epsilon_0}\right )(-\hat{k})$$$$=-\frac{5 \sigma}{2 \epsilon}\hat{k}$$Ans:(D)PhysicsNCERTStandard XII

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