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Byju's Answer
Standard XII
Chemistry
Ideal Gas Equation
Three moles o...
Question
Three moles of an ideal gas are expanded isothermally from a volume of
300
c
m
3
to
2.5
L
at
300
K
against a pressure of
1.9
atm. Calculate the work done in L-atm and joules.
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Solution
Given :
P
e
x
t
=
1.9
a
t
m
V
2
=
2.5
L
V
1
=
0.3
L
We know,
W
=
−
P
e
x
t
(
V
2
−
V
1
)
=
−
1.9
(
2.5
−
0.3
)
=
−
4.18
L
a
t
m
Now,
1
L
a
t
m
=
101.3
J
So,
W
=
101.3
×
−
4.18
=
−
423.4
J
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0
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