CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Number Properties (Language)

Three numbers...

Question

Three numbers p, q and r are pairwise coprime. If the product of p and q is 629 and that of q and r is 391, then find the value of (p + 2q + r).

A

77

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

67

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

94

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

84

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 94

Suggest Corrections

thumbs-up

1

Similar questions

Q. Three numbers p, q, and, r are pairwise coprime. If the product of p and q is 629 and the product of q and r is 391 then find the sum of p, q, r.

Q. p, q and r are in AP, then prove that (p + 2q - r) (2q + r -p) (r + p - q) = 4pqr.

p, q

r

A P

, then prove that

(p + 2 q - r) (2 q + r - p) (r + p - q) = 4 p q r

Q. p, q and r are three non - negative integers such that p + q + r = 10. The maximum value of pq+ qr + pr + pqr is

p, q, r

be three distinct real numbers , then the value of

(p + q) (q + r) (r + p)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Number Properties (Language)

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon