Question

Three particles each of mass $M$ are placed at the corners of a triangle of side length $L$. About an axis perpendicular to the plane of frame and passing through a corner of frame the moment of inertia of three bodies is :

• A. $M{L}^2$
• B. $2M{L}^2$
• C. $\sqrt{3}M{L}^2$
• D. $\frac{3M{L}^2}{2}$

Answer 1

The correct option is B $2M{L}^2$

$I_{D{D}^1}=2(m\times L^2)$ (considering the perpendicular distance of two bodies as $L$ and using the standard formula of moment of inertia)
$=2m{L}^2$