wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three particles of masses 1.0 kg and 2.0 kg and 3.0 kg are placed at the corners A,B and C respectively of an equilateral triangle ABC of edge 1 m.Locate the centre of mass of the system.

Open in App
Solution

m1=1 kg,

m2=2 kg,

m3=3 kg

x1=0,

x2=1,x3=12

y1=0,y2=0,y3=32

The position of centre of mass is

C.M=(m1x2+m2x2+m3x3)m1+m2+m3,(m1y2+m2y2+m2y3)m1+m2+m3

=((1×0)+(2×1)+(3×12)1+2+3,(1×0)+(2×0)+(3×32)1+2+3)

=(712,34) from the point B.


flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermal Expansion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon