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Question

Three persons A, B and C are standing in queue. There are five persons between A and B and eight persons between B and C. If there ne three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue ?


A
41
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B
40
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C
28
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D
27
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Solution

The correct option is C 28

Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under 

              3         8        5       21

Case I : .
Now, 28 < 40. So, 28 is the minimum number of perosn in the queue.


Logical Reasoning

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