Question

Three rectangles of legth $2$ m each are placed side by side. The width of these three rectangles are in the ratio $4:5:6$. If the width of the largest rectangle is $12$ m, then the composite area of the three rectangles (in sq. m) is

• A. $40$
• B. $50$
• C. $60$
• D. $80$

Answer 1

Answer: (C)

$60$

Let the width be $4x,5x$ and $6x$ also given $6x=12\Rightarrow x=2$
$\therefore$ width are $8,10,12$
the respective areas are $16,20,24$
$\therefore$ Total are $=16+20+24=60$