Question

Three resistors of $4.0\Omega$, $6.0\Omega$ and $10.0\Omega$ are connected in series. What is their equivalent resistance?

• A. $20\Omega$
• B. $7.3\Omega$
• C. $6.0\Omega$
• D. $4.0\Omega$

Answer 1

The correct option is A $20\Omega$

The equivalent resistance of N resistors connected in series is given by,
$R_{Equivalent}=R_1+R_2+R_3+...+R_N$
Hence,
$R_{Equivalent}=4.0+6.0+10.0=20.0\Omega$