Three years ago the average of A, B, C was 27 years and that of B and C, 5 years ago was 20 years A's present age is

40 years

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48 years

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30 years

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35 years

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Solution

The correct option is A 40 years
Let present age of A, B and C be x, y and z years
$\frac{(x - 3) + (y - 3) + (z - 3)}{3} = 27$
$\Rightarrow x + y + z = 90$
Also, $\frac{y - 5 + z - 5}{2} = 20$
$\Rightarrow y + z = 50$
$\Rightarrow x = 90 - 50 = 40$ years.

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Three years ago the average of A, B, C was 27 years and that of B and C, 5 years ago was 20 years A's present age is

The correct option is A 40 yearsLet present age of A, B and C be x, y and z years(x−3)+(y−3)+(z−3)3=27⇒x+y+z=90Also,y−5+z−52=20⇒y+z=50⇒x=90−50=40 years.

The correct option is A 40 years
Let present age of A, B and C be x, y and z years
$\frac{(x - 3) + (y - 3) + (z - 3)}{3} = 27$
$\Rightarrow x + y + z = 90$
Also, $\frac{y - 5 + z - 5}{2} = 20$
$\Rightarrow y + z = 50$
$\Rightarrow x = 90 - 50 = 40$ years.