Threshold frequency of a metal is $f_{0}$ . When light of frequency $2 f_{0}$ is incident on the metal plate, maximum velocity of electron emitted is $v_{1}$ . When frequency of incident radiation is $5 f_{0}$ , maximum velocity of emitted electron is $v_{2}$ . The ratio of $\frac{v_{1}}{v_{2}}$ is

1 : 4

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2 : 3

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1 : 2

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3 : 5

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Solution

The correct option is C $1 : 2$
$V_{1} \propto \sqrt{f_{0}}$
$V_{2} \propto \sqrt{5 f_{0} - f_{0}}$
$V_{2} \propto \sqrt{4 f_{0}}$

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Q. Threshold frequency of a metal is

f_{0}

. when light of frequency

v = 2 f_{0}

is incident on the metal plate, the maximum velocity of the electron that is emitted is

v_{1}

. When the frequency of incident radiation is

5 f_{0}

, and the maximum velocity of the emitted electron is

v_{2}

, find the ratio

\frac{v_{1}}{v_{2}}

Threshold frequency of metal is $f_{0}$ . When light of frequency $θ$ = $2 f_{0}$ is incident on the metal plate, velocity of electron emitted in $V_{1}$ . When a frequency of incident radiation is $5 f_{0} . V_{2}$ is velocity of emitted electron, then $V_{1} : V_{2}$ is