Time constant of a capacitor and capacitance are 5s and 100 nbsp-nF- It is charged from zero by a cell of emf nbsp-10 nbsp-V through a resistor- The charge on it after 3 s is-4-5-10-6C9-10-6C4-5-10-7C9-10-7C

The correct option is C 4.5×10 7CUse the equation, q= CE ( 1 e^ t/RC ) We know that time constant, τ nbsp;= RC = 5 s So, At t=3 sec, q=100× 10^ 9× 10 ( 1 e^ 3 ...

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Standard XII

Physics

Charging of Capacitors

Time constant...

Question

Time constant of a capacitor and capacitance are 5s and $100 n F$ . It is charged from zero by a cell of emf $10 V$ through a resistor. The charge on it after 3 s is.

4.5 \times 10^{- 6} C

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9 \times 10^{- 6} C

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4.5 \times 10^{- 7} C

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9 \times 10^{- 7} C

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Solution

The correct option is C $4.5 \times 10^{- 7} C$
Use the equation,
$q = C E (1 - e^{- \frac{t}{R C}})$
We know that time constant, $τ = R C = 5 s$
So,
At t=3 sec,
$q = 100 \times 10^{- 9} \times 10 (1 - e^{- \frac{3}{5}})$
$q = 10^{- 6} (0.451)$
$q = 4.51 \times 10^{- 7} C$

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Q. The time constant of a capacitor is 5sec. If the capacitance is C=100nF and it is charged from zero by a cell of EMF 10V through a resistor. What is the charge on it after 3 seconds?

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Time constant of a capacitor and capacitance are 5s and 100 nF. It is charged from zero by a cell of emf 10 V through a resistor. The charge on it after 3 s is.

The correct option is C 4.5×10−7CUse the equation, q=CE(1−e−tRC) We know that time constant, τ=RC=5 s So, At t=3 sec, q=100×10−9×10(1−e−35) q=10−6(0.451) q=4.51×10−7C

Time constant of a capacitor and capacitance are 5s and $100 n F$ . It is charged from zero by a cell of emf $10 V$ through a resistor. The charge on it after 3 s is.

The correct option is C $4.5 \times 10^{- 7} C$
Use the equation,
$q = C E (1 - e^{- \frac{t}{R C}})$
We know that time constant, $τ = R C = 5 s$
So,
At t=3 sec,
$q = 100 \times 10^{- 9} \times 10 (1 - e^{- \frac{3}{5}})$
$q = 10^{- 6} (0.451)$
$q = 4.51 \times 10^{- 7} C$