Question

# Time taken for an electron to complete one in revolution in Bohr orbit of hydrogen atom is :

A
4π2mr2nh
B
nh4π2mr
C
2πmrn2h2
D
h2πmr

Solution

## The correct option is A $$\frac{4\pi^2 mr^2}{nh}$$Time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is : $$t=$$distance/velocityDistance of Bohr orbit = circumference of Bohr orbit = $$2\pi r$$$$t=\frac {2\pi r}{v}$$Since $$mvr = \frac{nh}{2 \pi}$$$$v= \frac{nh}{2 \pi mr}$$ Thus, $$t=2\pi r \times \frac{2 \pi mr}{nh}$$$$t=\frac{4 \pi^2 mr^2}{nh}$$Chemistry

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