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Question

Time taken for an electron to complete one in revolution in Bohr orbit of hydrogen atom is :


A
4π2mr2nh
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B
nh4π2mr
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C
2πmrn2h2
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D
h2πmr
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Solution

The correct option is A $$\frac{4\pi^2 mr^2}{nh}$$
Time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is : $$t=$$distance/velocity

Distance of Bohr orbit = circumference of Bohr orbit = $$2\pi r$$

$$t=\frac {2\pi r}{v}$$

Since $$mvr = \frac{nh}{2 \pi}$$

$$v= \frac{nh}{2 \pi mr}$$ 

Thus, $$t=2\pi r \times \frac{2 \pi mr}{nh}$$

$$t=\frac{4 \pi^2 mr^2}{nh}$$

Chemistry

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