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Question

Tinku dropped a stone into a very deep well. He hears the sound 6.53 s after he dropped the stone. Find the depth of the well. Take acceleration due to gravity, g=10 ms2  and vsound=340 ms1.


  1. 180 m

  2. 90 m

  3. 100 m

  4. 220 m


Solution

The correct option is A

180 m


Given,
initial velocity, u=0
acceleration due to gravity, g=10 ms2
speed of sound, vsound=340 ms1

T1 = time taken by the stone to reach depth D when it is thrown

T2  = time taken by sound to reach the surface

From second equation of motion, we have, s=ut+12at2
 D=12×10×T21

T1 = 2×D10 = D5

We know, time=distancespeed
 T2  = D340

Total time, T1+T2 = D5 + D340=6.53

On solving we get, D=180 m.

 

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