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Question

To construct a triangle similar to a given ABC with its sides 37 of the corresponding sides of ABC, first draw a ray BX such that CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B1,B2,B3,... on BX at equal distances and next step is to join:

A
B10 to C
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B
B3 to C
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C
B7 to C
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D
B4 to C
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Solution

The correct option is B B7 to C
Join B7 to C, then draw B3Q parallel to B7C. Draw PQ parallel to AC. PBQ is the required triangle.
595108_236558_ans_7e2ec2d82b3c4cf28ce965e7135d6de1.png

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