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Byju's Answer
Standard VII
Mathematics
Construction of Perpendicular Bisector of a Line Segment
To construct ...
Question
To construct perpendicular bisector to a line segment AB =10 cm, we have to draw an arc of radius
A
>
5
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B
<
5
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C
=
5
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Solution
The correct option is
A
>
5
To construct perpendicular bisector to a line segment AB =10 cm, we have to draw an arc of radius greater than 5.
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Similar questions
Q.
To construct perpendicular bisector to a line segment AB =10 cm, we have to draw an arc of radius
Q.
To construct the perpendicular bisector of a line segment AB, first we have to draw the line segment AB. Then, with A as centre, at what radius should be set the compass for drawing the arcs ?
Q.
To draw a perpendicular bisector of segment AB, we take A and B as the centers, and radius more than half of length AB to draw arcs to locate the perpendicular bisector. What will happen if we take less than half of the segment as the radius?
Q.
A perpendicular bisector of a line segment can be constructed by drawing arcs of any radius.
Q.
To construct a trapezium ABCD with
A
B
∥
C
D
,
AB = 8 cm, BC = 5 cm, AD = 6 cm and
∠
A
B
C
=
60
∘
,
we follow the following steps:
1) Draw the line segment AB = 8 cm.
2) Construct the angle
∠
A
B
X
=
60
∘
at B.
3) With B as centre, draw an arc of radius 5 cm cutting BX at C.
The next step is ___.
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