To find the sum of the $1^{s t}$ 24 terms of the list of numbers whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ , what is the best approach to solve this question?

Find the first term and the common difference.

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List out the first 24 terms using the expression for n^th term and add them.

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Data insufficient - the value of “first term” need to be given.

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Data insufficient - the value of “common difference” need to be given.

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Solution

The correct option is A
Find the first term and the common difference.

We know that we have two formulae for finding Sum to $n$ terms of an AP.
$S_{n} = \frac{n}{2} (2 a + (n - 1) d)$
$S_{n} = \frac{n (a_{1} + a_{n})}{2}$
Watch the video to learn how to solve the problem.

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Similar questions

To find the sum of the $1^{s t}$ 24 terms of an AP whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ , what is the best approach to solve this question?

Find the sum of first $24$ terms of an AP whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ .

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To find the sum of the 1st 24 terms of the list of numbers whose nth term is given by an=3+2n, what is the best approach to solve this question?

The correct option is A Find the first term and the common difference. We know that we have two formulae for finding Sum to n terms of an AP. Sn=n2(2a+(n−1)d) Sn=n(a1+an)2 Watch the video to learn how to solve the problem.

To find the sum of the $1^{s t}$ 24 terms of the list of numbers whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$ , what is the best approach to solve this question?

The correct option is A
Find the first term and the common difference.

We know that we have two formulae for finding Sum to $n$ terms of an AP.
$S_{n} = \frac{n}{2} (2 a + (n - 1) d)$
$S_{n} = \frac{n (a_{1} + a_{n})}{2}$
Watch the video to learn how to solve the problem.