Question

Total volume of atoms present in fcc unit cell of a metal is (r is atomic radius)

• A. $\frac{20}{3}\pi r^3$
• B. $\frac{24}{3}\pi r^3$
• C. $\frac{12}{3}\pi r^3$
• D. $\frac{16}{3}\pi r^3$

Answer 1

The correct option is D $\frac{16}{3}\pi r^3$

No. of particles per unit cell of fcc = 4
Volume of each particle = $=\frac{4}{3}\pi r^3$
Total volume of all particles = $=4\times \frac{4}{3}\pi r^3=\frac{16}{3}\pi r^3$