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Question

ABC is a right triangle right angled at C, then the value of cosec2Asec2B is:

A
0
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B
-1
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C
2
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D
1
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Solution

The correct option is A 0
In ABC

A+B+C=180A+B+90=180B=90A

csc2Asec2B

=csc2Asec2(90A)
(sec(90A)=cscA)

=csc2Acsc2A=0

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