$△ G^{0}$ for the reaction $x + y ⇌ Z$ is $- v e 4.606 k c a l$ . The equilibrium constant for the reaction at $227^{0}$ C is:

100

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10

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2

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0.01

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Solution

The correct option is A $100$
${△ G}^{0} = - 2.303 n R T l o g K$
$- 4.606 = - 2.303 \times - 1 \times 2 \times 500 l o g K$
$l o g K = \frac{1}{500} = 0.2 \times 10^{- 2} = 2 \times 10^{- 3} \Rightarrow K = 100$

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