$△ ABC$ with $BC = 6.5 cm, AB = 5.5 cm$ and $AC = 5 cm$ . Find the radius of the incircle approximately.

4

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1.6

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Solution

The correct option is C $1.6$ cm
Given, $B C = 6.5 c m, A B = 5.5 c m a n d A C = 5 c m$
Area $= \sqrt{s (s - a) (s - b) (s - c)}$
where s $= \frac{a + b + c}{2} = 8.5$
$a = 6.5 c m, b = 5 c m, c = 5.5 c m$

so, Area $= \sqrt{(8.5) (2) (3.5) (3)} = 13.36 {c m}^{2} = △$

$∴ I n - r a d i u s$ r $= \frac{△}{s}$
$= \frac{13.36}{8.5} = 1.6$

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△ABC with BC=6.5 cm,AB=5.5 cm and AC=5 cm. Find the radius of the incircle approximately.

The correct option is C 1.6 cmGiven, BC=6.5cm,AB=5.5cmandAC=5cmArea=√s(s−a)(s−b)(s−c)where s=a+b+c2=8.5a=6.5cm,b=5cm,c=5.5cmso, Area=√(8.5)(2)(3.5)(3)=13.36cm2=△∴In−radius r =△s=13.368.5=1.6

$△ ABC$ with $BC = 6.5 cm, AB = 5.5 cm$ and $AC = 5 cm$ . Find the radius of the incircle approximately.