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Question

Tripling the speed of a motor car multiplies the distance needed for stopping it by


A
3
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B
6
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C
9
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D
some other number
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Solution

The correct option is C 9
Relation between velocity and distance is
$$ { V }^{ 2 }={ U }^{ 2 }+2aS$$
If the final velocity Zero then the relation is become
$$ U=\sqrt { 2aS } $$

Now if we want to multiply the velocity 3 time then we have to multiply the distance 9 time to make the equation balanced.

Physics

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