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Question

Two alternating currents having the value I1=3sinωt and I2=4sin(π/2ωt) are superimposed and passed through a hot wire ammeter. Then the reading of the ammeter will be

A
5 A
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B
5/2 A
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C
7/2 A
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D
7 A
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Solution

The correct option is B 5/2 A
Given:

I1=3sinωt, and

I2=4sin(π/2ωt)

So, peak value of net AC,

I0=I201+I202+2I01I02cos(Δϕ)

I0=32+42+2(3)(4)cos(π/2)

I0=5 A

Irms=I02=52 A

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