Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite directions, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution is
0.2
Applying conservation of momentum
1(21)-2(4) = 1(1)+2v
⇒ 2v = 12
V=6 ms−1
We have, E = v2−v1u1−u2
=6−121−(−4)=525=0.2