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Question

Two balls are projected simultaneously with the same speed from the top of a tower-one upwards and the other downwards. If they reach the ground in 6s and 2s, the height of the tower is:

A
120 m
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B
60 m
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C
80 m
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D
30 m
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Solution

The correct option is B 60 m
Lets consider u initial velocity of the ball
Take, g=10m/s2
From 2nd equation of motion at t=2sec
s=ut+12gt2
s=2u+12×10×22
s=2u+20. . . . . . .(1)
Time taken to come back at projection point is 62=4sec
Time to reach the maximum point is 42=2sec
at the maximum height final velocity is zero, v=0m/s
v=ugt
0=u2×10
u=20m/s
From equation 1, we get
s=2×20+20=60m
The correct option is B.

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