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Question

Two beakers A and B are present in a closed vessel. Beaker A contains 152.4 g aqueous solution of urea, containing 12 g of urea. Beaker B contains 196.2 g glucose solution, containing 18 g of glucose. If both solutions are allowed to attain equilibrium, then determine wt. % of glucose in its solution at equilibrium.

A
6.71
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B
15.49
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C
16.94
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D
20
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Solution

The correct option is B 15.49
The molar masses of glucose and urea are 180 and 60 g/mol respectively
The number of moles of urea are 12/60= 0.2 mole
The number of moles of glucose = 18/180 = 0.1 mole
When equilibrium is achieved, the mass (196.2 g) of glucose solution will reduce by x g and the mass of urea (152.4 g) will increase by x g. Due to this, the concentration (ratio of number of moles of solute to the mass of solution) of urea solution will become equal to the concentration of glucose solution.
0.2152.4+x=0.1196.2xx=80g
% weight glucose at equilibrium solution =18196.280×100=15.49

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