Question

# Two blocks of equal masses m1=m2=3 kg, connected by a light string, are placed on a horizontal surface which is not frictionless. If a force of 20 N is applied in the horizontal direction on a block, the acceleration of each block is 0.5 msâˆ’2. Assuming that the frictional forces on the two blocks are equal, the tension in the string will be

A

10 N

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B

20 N

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C

40 N

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D

60 N

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Solution

## The correct option is A 10 N From the second law of motion, T−f=m1a........(1) F−T−f=m2a........(2) Subtracting the two equations, we have 2T−F=(m1−m2)a Since m1=m2, we get 2T−F=0⇒T=F2=202=10 N Hence, the correct choice is (a).

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