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Question

Two blocks of equal masses m1=m2=3 kg, connected by a light string, are placed on a horizontal surface which is not frictionless. If a force of 20 N is applied in the horizontal direction on a block, the acceleration of each block is 0.5 ms2. Assuming that the frictional forces on the two blocks are equal, the tension in the string will be


A

10 N

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B

20 N

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C

40 N

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D

60 N

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Solution

The correct option is A

10 N



From the second law of motion, Tf=m1a........(1)
FTf=m2a........(2)
Subtracting the two equations, we have
2TF=(m1m2)a
Since m1=m2, we get 2TF=0T=F2=202=10 N
Hence, the correct choice is (a).


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