Question

# Two blocks of masses 10 kg and 30 kg are placed along a vertical line. If the first block is raised through a height of 7 cm by what distance should the second mass be moved to raise the center of mass by 1 cm.

A
1 cm up
B
1 cm down
C
2 cm down
D
2 cm up

Solution

## The correct option is B 1 cm down  Two masses $$m_1$$  and $$m_2$$ are kept in verticle line    $$m_1=10kg$$                            $$m_2=30kg$$   $$y_1=7cm$$                              $$y_2=?$$The centre of mass raised by $$1 cm$$  centre of mass = $$\dfrac{m_1 y_1+m_2 y_2}{m_1+m_2}$$                      1  =  $$\dfrac{10\times 7+30\times y_2}{10+30}$$                     $$40 = 70+30y_2$$                     $$y_2 = -1$$So, $$m_2=30kg$$ body should be displaced $$1cm$$ downward ,so as to raise the centre of mass through $$1cm$$ so the correct answer  is (B)Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More