Question

# Two blocks of masses $$m$$ and $$M$$ are placed on a horizontal frictionless table connected by light spring as shown in the figure. Mass $$M$$ is pulled to the right with a force $$F$$. If the acceleration of mass $$m$$ is $$a$$, the acceleration of mass $$M$$ will be

A
(Fma)M
B
(F+ma)M
C
FM
D
maM

Solution

## The correct option is A $$\dfrac{(F-ma)}{M}$$For the block with mass $$m$$, the force experienced is the spring force.$$\therefore$$ Spring force $$=$$ Mass $$\times$$ acceleration = $$ma$$For block with mass $$M$$, forces are spring force and the external $$F$$$$\therefore$$ acceleration $$= \dfrac {total \ force}{mass} = \dfrac{F-ma}{M}$$Physics

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