Two blocks of the same thickness and thermal conductivities k1 and k2 are placed in contact. Their outer surfaces are kept at constant temperatures T1 and T2. If T2 > T1, and k2 > k1 the temperature of the interfaces in the steady state will be
Let T be the temperature of the interface in the steady state and let d be the thickness of each block. Now, insteady state, the rate of flow of heat through each block must be the same, i.e.
k1A(T1−T)d=k2A(T−T2)dor k1(T1−T)=k2(T−T2)
Which give T=k1T1+k2T2k1+k2 , which is choice (a)