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Question

Two blocks of the same thickness and thermal conductivities k1 and k2 are placed in contact. Their outer surfaces are kept at constant temperatures T1 and T2. If T2 > T1, and k2 > k1 the temperature of the interfaces in the steady state will be


A

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B

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C

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D

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Solution

The correct option is A


Let T be the temperature of the interface in the steady state and let d be the thickness of each block. Now, insteady state, the rate of flow of heat through each block must be the same, i.e.

k1A(T1T)d=k2A(TT2)dor k1(T1T)=k2(TT2)

Which give T=k1T1+k2T2k1+k2 , which is choice (a)


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