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Question

Two bodies 1 and 2 are projected simultaneously with velocities v1=2 ms1 and v2=4 ms1. The body 1 is projected vertically up from the top of a cliff of height h=10 m and the body 2 is projected vertically up from the bottom of the cliff. If the bodies meet, find the time (in s) of meeting of the bodies.
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Solution

We will start with writing the equation of motion for both bodies in vertical direction:
Body1: s1=10+2tgt22
Body2: s2=4tgt22
when they meet s1=s2
hence, 10+2t=4t or t=5s

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