Question

# Two bodies 1 and 2 are projected simultaneously with velocities V1=2 m/s and V2=4 m/s . The body 1 is projected vertically up from the top of a cliff of height h=10 m and the body 2 is projected vertically up from the bottom of the cliff . If the bodies meet, find the time in (s) of meeting of the bodies.

A
2 s
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B
3 s
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C
5 s
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D
6 s
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Solution

## The correct option is C 5 sThe condition can be shown in the below figure. Let both the bodies meet at the point r Applying the equation of motion for body 1 , we get S1=2t−12gt2 Now, applying the equation of motion for body 2 , we get S2=4t−12gt2 when the two bodies meet, ⇒10+S1=S2 ⇒10+2t−12gt2=4t−12gt2 ⇒10+2t=4t ⇒2t=10 ⇒t=5 s

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