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Question

# Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9 g / cm3. If the mass of the other is 48 g, its density in g / cm3 is

A
4/3
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B
3/2
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C
3
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D
5
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Solution

## The correct option is C 3Apparent weight = V(ρ−σ)g = mρ(ρ−σ)g where m = mass of the body, ρ = density of the body σ = density of water If two bodies are in equilibrium then their apparent weight must be equal. ∴m1ρ1(ρ1−σ) = m2ρ2(ρ2−σ) ⇒369(9−1) = 48ρ2(ρ2−1) By solving we get ρ2 = 3

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