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Question

Two bodies are projected from the top of a tower in opposite directions with velocities of u1 and u2 simultaneously. Find the time when their velocities are mutually perpendicular.

A
2u1u2g
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B
u1u2g
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C
4u1u2g
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D
8u1u2g
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Solution

The correct option is B u1u2g

At time t,
Velocity of first body
v1=u1^igt^j
Velocity of second body v2=u2^igt^j
When velocities are perpendicular,
v1.v2=0u1u2+g2t2=0t=u1u2g

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